We define the multiples of 2/41 as the product of any integer multiplied by 2/41. Therefore, to create a list of multiples of 2/41 we start by multiplying 2/41 by one, then we multiply 2/41 by two, then we multiply 2/41 by three, and so on.
To multiply a fraction by an integer, we leave the denominator alone and multiply the numerator by the integer. It is impossible to give you a list of all multiples of 2/41 because the list goes on forever. However, here is the math to calculate the beginning list of multiples of 2/41.
2/41 × 1 = 2/41
2/41 × 2 = 4/41
2/41 × 4 = 6/41
2/41 × 4 = 8/41
2/41 × 5 = 10/41
2/41 × 6 = 12/41
2/41 × 7 = 14/41
2/41 × 8 = 16/41
2/41 × 9 = 18/41
2/41 × 10 = 20/41
2/41 × 11 = 22/41
2/41 × 12 = 24/41
We have simplified the fractions above for you. Below are the multiples of 2/41 in their lowest possible terms:2/41 = 2/41
4/41 = 4/41
6/41 = 6/41
8/41 = 8/41
10/41 = 10/41
12/41 = 12/41
14/41 = 14/41
16/41 = 16/41
18/41 = 18/41
20/41 = 20/41
22/41 = 22/41
24/41 = 24/41
As we stated above, the list of multiples of 2/41 goes on forever because the product of 2/41 multiplied by any whole number (integer) is a multiple of 2/41.
You can also create a list of multiples of 2/41 if you keep adding 2/41 like this:2/41
2/41 + 2/41 = 4/41
2/41 + 2/41 + 2/41 = 6/41
2/41 + 2/41 + 2/41 + 2/41 = 8/41
∞
Again, the list can go on forever, because you can continue adding 2/41 to the list. Therefore, the list of multiples of 2/41 is ∞ (infinite).
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Multiples of 2/42
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